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6m^2+42m-108=0
a = 6; b = 42; c = -108;
Δ = b2-4ac
Δ = 422-4·6·(-108)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-66}{2*6}=\frac{-108}{12} =-9 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+66}{2*6}=\frac{24}{12} =2 $
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